Question

a) Estimate the production in compacted cubic yards per hour for a roller if its average speed will be 9.5 mph and it will cover 6.7 ft in one pass. The job specifications limit the compacted lift thickness to 4.8 inches and require 7 passes per lift. The company usually figures production based on 45 min per hour. b) How many hours will you need to produce 28,364 compacted cubic yards using this equipment (using the productivity from part(a)? C) Estimate the production in compacted cubic yards per hour for a pneumatic compactor if its average speed will be 12 mph and it will cover 7.1 ft in one pass. The job specifications limit the compacted lift thickness to 6.5 inches and require 9 passes per lift. The company usually figures production based on 51 min per hour.

Answer 1

a) given,

speed of the roller = 9.5mph

width it will cover in one pass = 6.7ft

thickness of lift = 4.8inch = 0.4ft

Number of passes required per lift = 7

Therefore distance travelled in 1 hour(45 minutes) = 9.5*(45/60) = 7.125miles

Since 7 passes are required per lift, distance covered =7.125/7 =1.018miles = (1.018*5280) ft =5375.04 ft

production per hour(45 minutes) for roller = 5375.04*6.7*0.4 = 14405.11 cub ft = (14405.11*0.037037) cub yard =533.52 cubic yard

b)

Time required to compact 28,364 cubic yard = 28,364/533.52 = 53.16 hours   

c) given,

speed of the pneumatic roller = 12mph

width it will cover in one pass = 7.1ft

thickness of lift = 6.5inch = 0.54 ft

Number of passes required per lift = 9

Therefore distance travelled in 1 hour(51 minutes) = 12*(51/60) = 10.2 miles

Since 9 passes are required per lift, distance covered =10.2/9 =1.13miles = (1.13*5280) ft =5984 ft

production per hour(51 minutes) for roller = 5984*7.1*0.54 = 22942.65 cub ft = (22942.65*0.037037) cub yard =849.73 cubic yard

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