A dihybrid test-cross, involving parents with the phased genotypes of Ab/aB and ab/ab, produced 100 offspring....
A dihybrid test-cross, involving parents with the phased genotypes of Ab/aB and ab/ab, produced 100 offspring. Assuming that genes A and B are located on one or more autosomes and 10 of the offspring inherited the aabb genotype. What is the most likely genetic distance between genes A and B?
Answer= 20cM
Please Explain Why! Thanks
Homework Answers
Please look in the image for solution
As 10 are of ab/ab genotype offspring and it is of recombinant nature. Other recombinant offsoring i. e. AB/ab should also be 10.
Parental type Ab/ab and aB/ab should each of 40 in number.
That's why recombination frequency is (recombinant / total ) ×100
= (20/100) ×200= 20%
Recombination frequrncy is equal to genetic distance between gene. Hence between A and B gene, distance is 20cM.
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