How many molecules (not moles) of NH_3 are produced from 8.5 times 10^-4 g of H_2?...

Question

Question

Answer 1

Answer #1

Balanced equation:
N₂ + 3 H₂ = 2 NH₃

8.5 x 10^{- 4} gm of H2 = 8.5 x 10^{- 4} / 2 = 0.0004216 Moles

0.0004216 of H2 can produce 0.0002811 Moles of NH3

Number of ammonia Molecule = 0.0002811 x 6.023 x 10²³ = 1.693 x 10²⁰ Molecules

1.693 x 10²⁰ Molecules can be produced with 8.5 x 10^{- 4} gm of H2

Answer 2

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