Consider the equilibrium reaction. 2 A+B 240 After multiplying the reaction by a factor of 2,...
Consider the equilibrium reaction. 3 A+B 2c After multiplying the reaction by a factor of 2, what is the new equilibrium equation? new equilibrium equation: 6A + 2B 4C Create the equilibrium constant expression, K., for the new equilibrium reaction. Answer Bank IC) IA C IAP K = IA [B] [B] ICI 18" If the initial reaction contains 1.83 M A. 1.95 MB, and 2.55 MC, calculate K, for the new equilibrium reaction. ке 3.378 Incorrect
Consider the equilibrium reaction. 3A+B-20 After multiplying the reaction by a factor of 2, what is the new equilibrium equation? new equilibrium equation: Create the equilibrium-constant expression, K., for the new equilibrium reaction. Answer Bank LAP B B14 If the initial reaction contains 2.05 MA, 1.19 MB, and 2.91 MC, calculate K for the new equilibrium reaction. K
Consider the equilibrium reaction. 3A+B 2C After multiplying the reaction by a factor of 2, what is the new equilibrium equation? new equilibrium equation: Create the equilibrium-constant expression, Ke. for the new equilibrium reaction. Answer Bank [C) (B) A] (C) [AP [BJ (BI If the initial reaction contains 2.01 M A, 1.07 M B, and 2.35 MC, calculate K, for the new equilibrium reaction K. of careen privacy policy
Consider the equilibrium reaction. 3 A+B = 20 After multiplying the reaction by a factor of 2, what is the new equilibrium equation? new equilibrium equation: Create the equilibrium-constant expression, K., for the new equilibrium reaction. Wanswer Bank [A] [B] (C) Ke ( B IA IC icr CAT [B We were unable to transcribe this image
Consider the balanced chemical equation for this equilibrium reaction: A (aq) + B (aq) = AB (aq) To determine the equilibrium constant for this reaction at 298 K, a student mixes two solutions together and allows them to react: • 10.0 mL of 0.60 M A (aq), and, • 40.0 mL of 0.25 MB (aq). When this solution reaches equilibrium, the student measures the equilibrium concentration of AB in the 50.0 mL solution: [AB]E = 0.10 M. Which values should...
If the initial reaction contains 1.57 M A, 1.19 MB, and 2.79 M C. calculate K, for the new equilibrium reaction. Kc =
Consider the equilibrium reaction 2 A+B=4C Write the equation for the reverse reaction. reverse reaction: = Write the equilibrium-constant expression in terms of [A], [B], and [C] for the reverse reaction. Answer Bank [A] [C] [B] Kreverse TAP [B]* ICI TAL [B] CI If the equilibrium concentrations are 1.95 M A. 1.55 M the reverse reaction. B, and 2.15 MC, calculate the value of the equi Kreverse
Given the chemical reaction below, A(aq) + 2 B(aq) ⇌ C(aq) + D(l) the equilibrium constant for the reaction is Kc = 0.8. The reaction mixture at equilibrium contains 1.47 mol of A, 1.84 mol of B in a 1.00 L flask. What is the concentration of C in the equilibrium mixture? Only enter the numerical value with three significant figures in the answer box below. Do NOT type in the unit (M).
Q(22) Kp=Kc when? A) The reaction is at equilibrium B) The reaction is exothermic C) The reaction is endothermic D) all of the gasses present are at the same temperature E) the number of moles of gas on both sides of the balanced equation is the same. Q(23) HAH +A at the equilibrium (HA) = 1.65* 10-2 M and [H") = (A-) = 5.44*10-4 M at equilibrium. Kc = A) 1.7 X 10-1 C) 1.7 X 103 D) 1.7 X...
JUU UHUMU UU UHCMlal yumurium Equilibrium Constant and Reaction Quotient At equilibrium, the concentrations of reactants and products can be predicted using the equilibrium constant, Kc, which is a mathematical expression based on the chemical equation. For example, in the reaction aA +B=cC + dD where a, b, c, and d are the stoichiometric coefficients, the equilibrium constant is K. = _CºD [A] [B] where [A], [B], [C], and [D] are the equilibrium concentrations. If the reaction is not at...