On multiplying the reaction by 2
Kc (new) = [Kc (old)]2
Kc (new)= (2.55)4/(1.83)6(1.95)2
Kc = 0.296
Consider the equilibrium reaction. 3 A+B 2c After multiplying the reaction by a factor of 2,...
Consider the equilibrium reaction. 3A+B 2C After multiplying the reaction by a factor of 2, what is the new equilibrium equation? new equilibrium equation: Create the equilibrium-constant expression, Ke. for the new equilibrium reaction. Answer Bank [C) (B) A] (C) [AP [BJ (BI If the initial reaction contains 2.01 M A, 1.07 M B, and 2.35 MC, calculate K, for the new equilibrium reaction K. of careen privacy policy
Consider the equilibrium reaction. 3 A+B = 20 After multiplying the reaction by a factor of 2, what is the new equilibrium equation? new equilibrium equation: Create the equilibrium-constant expression, K., for the new equilibrium reaction. Wanswer Bank [A] [B] (C) Ke ( B IA IC icr CAT [B We were unable to transcribe this image
Consider the equilibrium reaction. 3A+B-20 After multiplying the reaction by a factor of 2, what is the new equilibrium equation? new equilibrium equation: Create the equilibrium-constant expression, K., for the new equilibrium reaction. Answer Bank LAP B B14 If the initial reaction contains 2.05 MA, 1.19 MB, and 2.91 MC, calculate K for the new equilibrium reaction. K
Consider the equilibrium reaction. 2 A+B 240 After multiplying the reaction by a factor of 2, what is the new equilibrium equation? new equilibrium equation: Create the equilibrium-constant expression, Kc, for the new equilibrium reaction. Answer Bank K = [BIS [C18 [Ch" [A] [B? [A] [A]” [C] [B] If the initial reaction contains 1.65 M A, 1.47 MB, and 2.93 M C, calculate K, for the new equilibrium reaction. K. =
Consider the equilibrium reaction 2 A+B=4C Write the equation for the reverse reaction. reverse reaction: = Write the equilibrium-constant expression in terms of [A], [B], and [C] for the reverse reaction. Answer Bank [A] [C] [B] Kreverse TAP [B]* ICI TAL [B] CI If the equilibrium concentrations are 1.95 M A. 1.55 M the reverse reaction. B, and 2.15 MC, calculate the value of the equi Kreverse
Question 8 of 11 Resume > Consider the equilibrium reaction Attempt 1 2A+B 4C Write the equation for the reverse reaction. reverse reaction: Write the equilibrium-constant expression in terms of [A]. [B), and [C] for the reverse reaction. Answer Bank (AP IC) IA [B) Kreverse IA [B) If the equilibrium concentrations are 1.01 M A, 2.05 M B, and 2.29 M C, calculate the value of the equilibrium constant of the reverse reaction. Kreverse help contact us terms of use...
Consider the reaction: A + 2B + 2C+D The equilibrium expression for this reaction is: O A) [A]2[B] 2[ CD] OB) [CID] [A]2[B] OC) [C]?p] [A]B12 CD) (AJB)2 E) TALB
Question 2 of 3 Two reactions and their equilibrium constants are given. A+2B 2C K1 2.77 2C D K2 0.198 Calculate the value of the equilibrium constant for the reaction D A + 2 B. K =
B. The reaction A(g) + 2B(g) 2C(g) was allowed to come to equilibrium. The initial After the reaction reached equilibrium, the amount of B remaining in the 2.0 L vessel was 1.0 amounts of reactants placed into a 2.00 L vessel were 2,0 mol A and 2.0 mol B and 1,0 mol C. mol of B. Calculate (show formulas and appropriate steps in each case): a) (10 points) Ke for this reaction: Ec = LA)632 (2)(2) = to equilibrium for...
Review Constants Periodic Ta At equilibrium, the concentrations of reactants and products can be predicted using the equilibrium constant, Ke, which is a mathematical expression based on the chemical equation. For example, in the reaction Part A A+B=C+ dD where a, b, c, and d are the stoichiometric coefficients, the equilibrium constant is KID A mixture initially contains A, B and in the following concentrations: A = 0.500 MB] =0.950 M and C -0300 M The following reaction occurs and...