Question

Consider the reaction: A + 2B + 2C+D The equilibrium expression for this reaction is: O A) [A]2[B] 2[ CD] OB) [CID] [A]2[B] OC) [C]?p] [A]B12 CD) (AJB)2 E) TALB

Answer 1

Here the given Iven equation is it 1 exa A + B = 20 + D . How we write the equillibrium expression, to understand this first of all we have to understand the law of mass action it - According to this law, the rate of a chemical reaction is directly fropotional to the product of the active masses of rectant molecules 1. for example in the given equation it S A + 2B = 20 to . for this reaction rate of forward reaction cul - Via Caomi Cooma and reaction rectant molecole . A and B A mi is stiochometric Coefficient of A that is 1. ma is stiochometric coefficient of B that is a. =ll vi = K, CAT.CBD? -0 Scanned with Kis rate constant for forward Reaction, CamScanner ETTER

Now for for hackwe and reaction rate will be cual le a Cc7"' coghe backward reaction rectant molecule are c and D ni is stiochometric coefficient of c that is a ha is stiochometric coefficient of that is in so lozka cega cool - & TEXT forward reaction = And we know that at equilliksium rate of Rate of hackward reaction. =11. KICAJCBJ 2 = ka ccoo cool .. K = Kg (cod cool 1. TAJ (Bga -1 K = ccgam cogi CS Scanned with Cao CBDQ CamScanner . Ka 22 NINETEEN

enaul ki = keq = Kc L in Ka became tamis of here we are reforesenting things Concentration, ms kes = equillibrium constant so I | к. = cc? со? I 1 . CA ] [B]? exfrenion l . this is the for this equillitesium reacton. option c is correed. | Scanned with CamScanner