Consider the balanced chemical equation for this equilibrium reaction: A (aq) + B (aq) = AB...
Consider the equilibrium reaction. 2 A+B 240 After multiplying the reaction by a factor of 2, what is the new equilibrium equation? new equilibrium equation: Create the equilibrium-constant expression, Kc, for the new equilibrium reaction. Answer Bank K = [BIS [C18 [Ch" [A] [B? [A] [A]” [C] [B] If the initial reaction contains 1.65 M A, 1.47 MB, and 2.93 M C, calculate K, for the new equilibrium reaction. K. =
The electrochemical cell described by the balanced chemical reaction has a standard cell potential of -0.2 V. Calculate the equilibrium constant (Kc) for the reaction at 298 K. Round your answer to 3 significant figures. H2SO3(aq) + H2O(l) → H2(g) + SO42-(aq) + 2H+(aq) The electrochemical cell described by the cell notation has a standard cell potential of -0.10 V. Calculate the value (kJ) for the ΔG˚ of the cell. Round your answer to 3 significant figures. Pt(s) l Cr3+(aq),...
Given the chemical reaction below, A(aq) + 2 B(aq) ⇌ C(aq) + D(l) the equilibrium constant for the reaction is Kc = 0.8. The reaction mixture at equilibrium contains 1.47 mol of A, 1.84 mol of B in a 1.00 L flask. What is the concentration of C in the equilibrium mixture? Only enter the numerical value with three significant figures in the answer box below. Do NOT type in the unit (M).
Consider the reaction 2 Ag(s) + Cu2+ (aq) =2 Ag2+ (aq) + Cu(s). Write the equilibrium constant expression and indicate if the equilibrium is homogeneous or heterogeneous. Kc = le* heterogeneous Arcu. homogeneous окс = Taal (Cu2+] Kc = A c heterogeneous [Act (Cu2+1' Kc - AC Cut homogeneous
5. If the reaction in question 4 is A(aq) + B(aq) -AB(aq) and the molarity of A in solution A is 0.60 M and the molarity of B in solution B is M, calculate the enthalpy of reaction Afrr, for the formation of 1 mole of AB in solution 6. The addition of 20.0 J of heat to a 6.00 g sample of lead at 23.0 C caused the temperature to rise to 48.7 °C. What is the specific heat...
1) Consider the following equilibrium: Fe3+(aq) + SCN-(aq) ⇌ FeSCN2+(aq) Initial concentrations: [Fe3+] = 0.590; [SCN-] = 1.239; [FeSCN2+] = 0 The equilibrium concentration of [FeSCN2+]eq = 0.454 M. What is the numerical value of KC for this equilibrium? KC = __________________ 2) Consider the following equilibrium: Fe3+(aq) + SCN-(aq) ⇌ FeSCN2+(aq) Initial concentrations: [Fe3+] = 0.370; [SCN-] = 0.777; [FeSCN2+] = 0 The equilibrium concentration of [FeSCN2+]eq = 0.285 M. What is the equilibrium concentration of Fe3+? [Fe3+]eq =...
Consider the following reaction: Fe3+(aq)+SCN−(aq)⇌FeSCN2+(aq) A solution is made containing an initial [Fe3+] of 1.2×10−3 M and an initial [SCN−] of 8.2×10−4 M . At equilibrium, [FeSCN2+]= 1.8×10−4 M . Calculate the value of the equilibrium constant (Kc)(Kc). Express your answer using two significant figures.
Consider a general reaction enzyme A(aq) = B(aq) The AG*' of the reaction is –5.650 kJ. mol-?. Calculate the equilibrium constant for the reaction at 25 °C. Keq = What is AG for the reaction at body temperature (37.0 °C) if the concentration of A is 1.9 M and the concentration of B is 0.60 M? AG= kJ. mol-1
Consider the reaction. A(aq) 3 B(aq) Kc 9.88 x 10- at 500 K If a 5.40 M sample of A is heated to 500 K, what is the concentration of B at equilibrium? [B] =
Section Name Experiment 23 Advance Study Assignment: Determination of the Equilibrium Constant for a Chemical Reaction 1. A student mixes 5.00 mL 2.00 X 10M Fe(NO), with 5.00 ml 2.00 x 10-M KSCN. She finds that in the equilibrium mixture the concentration of FeSCN is 1.40 x 10M. Find K for the reaction Fe(aq) + SCN (aq) FeSCN2(aq). Step 1 Find the number of moles Fe and SCN initially present. (Use Eq. 3.) (5.00 x103 LX (300X163) = (x 103...