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Calculate Delta H^0 for the reaction. Enter your a
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Answer #1

The equation fo Enthalpy of reaction

dHRxn = Hproducts- Hreactants

Products = CH3F and H2O

Reactants = CH3OH and HF

enthalpy of products =

CH3F = -223 kJ/mol

H2O = −285.830 kJ/mol

CH3OH =−238.7 kJ/mol

HF = −273.30

then..

dHRxn = Hproducts- Hreactants

dHRxn = Hproducts- Hreactants = ( -223 + -285.830 ) - (-238.7 + -273.30 ) = 3.17 kJ/mol

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