1. A ball with a mass of m 0.175-kg is dropped from a height of h...
A soft tennis ball is dropped onto a hard floor from a height of 1.55 m and rebounds to a height of 1.03 m. (Assume that the positive direction is upward.) (a) Calculate its velocity just before it strikes the floor. (b) Calculate its velocity just after it leaves the floor on its way back up. -Answer is 4.49 m/s (c) Calculate its acceleration during contact with the floor if that contact lasts 3.50 ms. (d) How much did the...
A ball of mass 0.180 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.785 m. What impulse was given to the ball by the floor? Magnitude
A soft tennis ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.13 m. (Assume that the positive direction is upward.) (a) Calculate its velocity just before it strikes the floor, in m/s. (b) Calculate its velocity just after it leaves the floor on its way back up, in m/s. (c) Calculate its acceleration (in m/s^2) during contact with the floor if that contact lasts 3.50 ms. (d) How much...
A ball with mass of 0.050 kg is dropped from a height of 2.0 m. It collides with the floor, then sticks to the table. The Collison takes 0.020 s. a) Use the conservation of mechanical energy (Ei = Ef) to calculate the velocity of the ball before collision with the floor
A ball of mass 0.140 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.830 m. What impulse was given to the ball by the floor? magnitude kg. m/s direction --Select-
A soft tennis ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.10 m. (Assume that the positive direction is upward. Indicate the direction of velocities and accelerations with the sign of your answer.) (a) Calculate its velocity (in m/s) just before it strikes the floor. (b) Calculate its velocity (in m/s) just after it leaves the floor on its way back up. (c) Calculate its acceleration (in m/s2) during...
A steel ball is dropped onto a hard floor from a height of 1.95 m and rebounds to a height of 1.89m. (Assume that the positive direction is upward.) (a) Calculate its velocity (in m/s) just before it strikes the floor (b) Calculate its velocity (in m/s) just after it leaves the floor on its way back up(c) Calculate its acceleration (in m/s) during contact with the floor if that contact lasts 0.0800 ms (d) How much (in ) did the ball compress...
2. A 2.50 kg ball is at a height of 5.00m. It is then dropped. a) What is its kinetic energy after it has fallen 2.00m? (5 pts) b) If it rebounds with a upward velocity of 8.00m/s immediately after hitting the floor, how much energy was lost on impact? (7 pts) 2.3kg KEnir KE2i = REIFT EE2 KE at 2 m ? Im Veitt mV i = 12 mV ET KE = PE 1.25kg /
A 0.10-kg ball is dropped from a height of 10 m and rebounds to a height of 8.0 m. a. Is energy conserved in the ball? b. If not, how much energy was lost, and what happened to it?
A 0.600-kg ball is dropped from rest at a point 4.50 m above the floor. The ball rebounds straight upward to a height of 3.40 m. Taking the negative direction to be downward, what is the impulse of the net force applied to the ball during the collision with the floor?