Normally distributed scores on Social Psych Final Exam had a mean of 235 and a standard deviation of 52. What is the minimum score needed to be in the highest 10%? Round to the nearest whole number.
Given that,
mean = = 235
standard deviation = =52
Using standard normal table,
P(Z > z) = 10%
= 1 - P(Z < z) = 0.10
= P(Z < z ) = 1 - 0.10
= P(Z < z ) = 0.90
= P(Z <1.28) = 0.90
z = 1.28 (using standard normal (Z) table )
Using z-score formula
x = z * +
x= 1.28 *52+235
x= 301.56
x=302
Normally distributed scores on Social Psych Final Exam had a mean of 235 and a standard...
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