![8. Here is a code block. clc; clearvars nums 100 rand (1,65) N- length (nums) for k 1 :N tt printf 35s\n\n, Table of Numbers fprintf $15s$25s\n, Number Square fprintf 20d 25s\n nums (k) nums (k) 2) tt tt 1 nums (k) avg end fprintf The average of the ss numbers is $0.2f.An N, avg) Here is the output produced: Table of Numbers Number Square 9.398295e+01 8.832794 et 03 Table of Numbers Number Square 6.455519e 01 16737 2e 03. [and so on, for a total of 65 sets of the se] Table of Numbers Number Square 4.794632e+01. 2.298850e+03 The average of the A numbers is 0.74 Rewrite the code to produce this desired output. Table of Numbers Number Square 120. 34 10.97 6.36 40.44 etc. 40.46 1636.85 The average of the 65 numbers is 19.26.](http://img.homeworklib.com/questions/8a932d60-9602-11eb-b53f-dd3f287f06d7.png?x-oss-process=image/resize,w_560)
Homework Answers
clc;clearvars
nums = 100*rand(1,65);
N = length(nums);
ttl = 0;
fprintf('%35s\n\n','Table of Numbers')
fprintf('%15s%25s\n','Number','Square','------','------')
for k = 1:N
fprintf('%20d%25s\n',nums(k),nums(k)^2)
ttl =ttl + nums(k);
avg =ttl/N;
end
fprintf('The average of the %s numbers is %0.2f.\n',N,avg)
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