Question

In an agricultural experiment, the effects of two fertilizers on the production of oranges were measured. Sixteen randomly selected plots of land were treated with fertilizer A. The average yield, in pounds, was 457 with a standard deviation of 38. Twelve randomly selected plots were treated with fertilizer B. The average yield was 394 pounds with a standard deviation of 23. Find a 99% confidence interval for the difference between the mean yields for the two fertilizers. (Round down the degrees of freedom to the nearest integer and round the final answers to two decimal places.) The 99% confidence interval is (30.79 97.5 %

Answer 1

solution we used Giveni I for fertilizer A & 2 for fertilizer B fertilizer 1 n. 16 1₂ = 12 x = 457 pounds X = 394 Pounds. su 38 Pounds pounds L =0.0 S = 23 S.E= 5,² ni ante 1444 16 529 12 134.3333 S.E. 11.5902 tnam-2, dhe t26,0.005 2.779 The ggf. confidence interval for el, ll is &-*)-S.Ex tamirchtz, -1)+5. € + tarang24 63-11.5902% 2.779 4 63 +11.5902*2.779

f Bo.7908 95.2092 en The gg C. I. for li-M is (30.79 95.21 + Given in me =13 1₂=7 X = 6.83 mg/L X2= 3.32 mg/L S = 1.72 mg/L 52 = 1. 17 ung/L x=0.05 5,2 t S nz ni 2.9584 13 1. 3689. 7 0.42313 S. 0.6505 tn tn 2, x4 = t 18,0.025 2.101 The 95% confidence interval for elindly is (Zn-Feb-5.&* tn the 2014(E-v]+ S.E.Xtatezacet 02 3.5L 0.6505 *2.101 B.51+0.6505*2.101 CO

Date 3.511.3667 3.514 1.3667 2.1433 (2. 4.8767 f The 954. c. I. for llinel is = 2.143 ） 4.877 4 CS