Question

10.3 Show that for the geometries of Figures 10.1 and 10.2, n = R/a, which leads to the following important approximate relation: Radius of particles Adhesion or binding energy of particles Binding energy of atoms x * Radius of atoms (10.23)

Answer 1

figure 1001 > for fig @ Qb DW = Wasso -Ndisp low -9 (4-6) = + 9(4-8) 2 Binding energy of atoms --OW R3 Radius of Atome a parte imeter=up. particle with Diameter=4R. particles Diamefer of particle = 42 = 2R Radius of particles L [Radius of particle = 28 3 Adhesion or Binding Energy of particles - Binding Energy of Atoms x particles Radius of Radius of Atoms » Adhesion of Binding Energy of particles = + 9(A-B2 24 XAR A Adhesion of Bircling Energy of particles = +18 (A-8) 2 kg- 10.2 AW = -(A-B) [Binding Energy of Afons = - sw = (A-B²7 Radius of partides =R ! Radius of Atom =R] Adhesion of Binding Energy of Paoticles = (A-B) x 2 = (A-82