Question

44 k12 t=0 6 V 11 k 2 TO+ 33 F For the circuit shown above, find the capacitor voltage for t>0 (i.e after the switch opens). The solution, since this a "natural" response, should be of the form a exp(-bt) followed by appropriate units. VoO: Part #2 (0/10) For this second circuit, what is the inductor current for t>0 (again a "natural" response, going to zero as time goes to infinity)?

Answer 1

1 We have given a circuit. .. Aftur Loto Aftur liku &t=3347 vo We need to find Casmitor roltage fort? tro at txo switch was closed and circuit is in stead. State and we know that insteady Stelte Capacitor behaves as open circuit . at txo circuit becomes : 44kn Gv 6 ist 334 F under steady state 44kn or liker Vo Lo-) Voltage accouss Capacitor at t=o- is division rule / Volo-2 .11 kv, kuit 414 kuX 6 [ from voltage 1 No 10-) x63 v CS Scanned Kottayo accoobs Capacitor cannot change CamScanner - 5/55

jos tontly, so no Hege at to do is same as at t=0+ Voco-) = V0 10+) = @= 1.2v1 at t=o becomes switch is source free opened the cirait RC circuit. 1 kn } vo 7 33ME time constant of the above circuit is given ay To RC = 11x107x33 X107 := 11x33x10-3.s as t a again errait goes into steely state. in steady state capcustos behaves as open circuit , so at t=0 - 0 363 See volo) -N Volc0) FOV we know a cross from capaitor transient Egn. is given by voltage : Vol.) + Pro (0) - Volas) CS Scanned wor? !) = Volt) - Scanned with CamScanner

Vo11) = 0+1 -07 é o. 3on Volts a é 27544 for t>0 Volt) - - 2.754 t 1-2 ē . r for tool rs Scanned with CamScanner