Question

circuit. VII Find the renin Thevenin equivalent 2v 6oon + 5 3002 3 Des158 @ q cos(500+) (2) I iso mF

Answer 1

Solution: Zth:- Thevenin Jurpedance, for calculating 2 th , we have to deactivate independent voltage sources, and dopen dout sources will remain as it is. & connect 14 uurrent source across terminal. In Va Xc = . 2V 600 SL V. I X 150 X10 500x 1 v * -j300.2 30072, Q1A = 3002 super & usúng Nodal analysis at node o o te toote 150 v ( 00 * Jboo) V, Vz 12] V21 2 - t 600 300

Ve (1+2j) + 2V2 = 600 - 0 V₂ - V q = 24 . As Vevey VZ-V4 = 21 ) Vq = V2 Putting value of v= uz to in eo V₂ (1+28) + 2V 2 = 600 3 V2 (1+2j + 6) = 1800 V2 = 1300 7+92 - 247,2490 V (-15.945* 18. Vos V2 = 247.2490 (-15.945' v Then ZTH = 247. 24904-15.945 947.24 90/-15.945' 2

Now, VT: Thevenir voltage 2V 6oor ve a Lo v % v izoor 3000 Vt 963 (500+) = 9 Lov using Nodal analysis at node - q LO + 600 + V₂ + 2V . zo 300 3300 AS VE Ve Then - 9 20 600 -1300 300 300 Via 920 = 1.236 L-15.945 w 71i2

Then. -Vq - 2V TV The co The 2V TV, As V=V, Then Vths 3V, = 3x2.236 / -15.945º V z 3.7087 (-15.945º v THE VENIN'S EQo CRT. zth With ©