Question

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Consider the following plant cells floating in an open beaker containing 0.2M sucrose. By definition, an open beaker has a pressure potential O MPa. Assume that the cells have come to equilibrium with the solution in the beaker. Beaker Cell 1 Cell 2 Cell 3 Component Solute potential -0.5 MPa 1 -1.0 MPa 1 -0.75 MPa -0.5 MPa Pressure potential Yp 0.0 MPa Total water potential w -0.5 MPa 1) In Cell 1 A) Vp = 0.0 MPa and Vw = -1.0 MPa. B) p = 0.0 MPa and Ww=0.0 MPa. C) vp = -0.5 MPa and Ww=-0.5 MPa. D) Vp = 0.0 MPa and Vw = +0.5 MPa. E) V = +0.5 MPa and ww = -0.5 MPa.

Answer 1

I on this case 1st cell We know that wales potential = solute potential + Pressure potential & YW = Yp+YS = 0.0+(-4.0) – – 1.0 mpa on the case of seconacell W = Yp+YS = 0.0+(-0.75 -0.75 mpa on the case of seco third cell Yw = 4ptys -0.0-0.5 =-0.5 Mpa.