SOLUTION:
From given data,
Problem 8-1
Consider the following time series data.
Week | 1 | 2 | 3 | 4 | 5 | 6 |
Value | 18 | 12 | 16 | 11 | 19 | 14 |
Using the naive method (most recent value) as the forecast for the next week,compute the following measures of forecast accuracy.
Week | Value | Fore cast | Fore cast error | Absolute error | square of Absolute error |
%error |
Absolute % error |
1 | 18 | ||||||
2 | 12 | 18 | -2 | 2 | 4 | -2/12*100 = -16.66 % | 16.66 % |
3 | 16 | 13 | 3 | 3 | 9 | 3/16*100 =18.75 % | 18.75 % |
4 | 11 | 16 | -5 | 5 | 25 | -5/11*100 = -45.45 % | 45.45 % |
5 | 19 | 11 | 8 | 8 | 64 | 8/19*100 = 42.10 % | 42.10 % |
6 | 14 | 17 | -3 | 3 | 9 | -3/14*100 = -21.42 % | 21.42 % |
TOTAL | 21 | 111 | 144.38 % |
(a) Mean absolute error
Mean absolute error = Total absolute error / number of error
Mean absolute error = 21 / 5
Mean absolute error = 4.2
(b) Mean squared error
Mean squared error = Total square of Absolute error / number of error
Mean squared error = 111 / 5
Mean squared error = 22.2
(c) Mean absolute percentage error
Mean absolute percentage error = Total absolute percentage error / number of error
Mean absolute percentage error = 144.38 / 5
Mean absolute percentage error = 28.87 %
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