Question

Suppose you perform an ANOVA on 18 subjects divided evenly into three groups according to age. Reading speed is measured and

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Answer #1

A.

Degrees of freedom "between the groups" = 3-1

= 2

Degrees of freedom "within the groups" = 18-3

= 15

B.

For \alpha = 0.05 and

df(numerator) = 2

df(denominator) = 15

Fcrit = 3.682

C.

Since Fobt = 9.15 > 3.682 i.e. we can reject the null hypothesis and hence we can say that there is enough evidence to conclude that reading speed is different among three groups.

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