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[4] Compute the state transition matrix At given that, and verify your answers with MATLAB – 4) A = [1 2] ) A = 12 -1 _1-1 01

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Answer #1

as verified in matlab

a) syms t

A=[1 2;3 -1]

TM=expm(A*t)

A =

     1     2

     3    -1

TM =

[ exp(7^(1/2)*t)/2 + exp(-7^(1/2)*t)/2 + (7^(1/2)*exp(7^(1/2)*t))/14 - (7^(1/2)*exp(-7^(1/2)*t))/14,                                          (7^(1/2)*exp(7^(1/2)*t))/7 - (7^(1/2)*exp(-7^(1/2)*t))/7]

[                                    (3*7^(1/2)*exp(7^(1/2)*t))/14 - (3*7^(1/2)*exp(-7^(1/2)*t))/14, exp(7^(1/2)*t)/2 + exp(-7^(1/2)*t)/2 - (7^(1/2)*exp(7^(1/2)*t))/14 + (7^(1/2)*exp(-7^(1/2)*t))/14]

b) syms t

A=[-1 0;2 -1]

TM=expm(A*t)

A =

    -1     0

     2    -1

TM =

[     exp(-t),       0]

[ 2*t*exp(-t), exp(-t)]

c) syms t

A=[5 7 -5;0 4 -1;2 8 -3]

TM=expm(A*t)

A =

     5     7    -5

     0     4    -1

     2     8    -3

TM =

[ 2*exp(2*t) + exp(3*t) - 2*exp(t), 5*exp(2*t) + exp(3*t) - 6*exp(t), 4*exp(t) - exp(3*t) - 3*exp(2*t)]

[   2*exp(2*t) - exp(3*t) - exp(t), 5*exp(2*t) - exp(3*t) - 3*exp(t), exp(3*t) - 3*exp(2*t) + 2*exp(t)]

[ 4*exp(2*t) - exp(3*t) - 3*exp(t), 10*exp(2*t) - exp(3*t) - 9*exp(t), exp(3*t) - 6*exp(2*t) + 6*exp(t)]

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