Question

A population of values has a normal distribution with u = 72 and a 3.1. You intend to draw a random sample of size n = 154. Find the probability that a single randomly selected value is between 71.3 and 71.7. P(71.3 < X< 71.7) = Find the probability that a sample of size n 154 is randomly selected with a mean between 71.3 and 71.7. P(71.3 M<71.7) Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

Answer 1

3.1 Mニ154 < X< 7L-7 = P| T-3-12 くX-72 くフ17ー72 3-1 3-1 3.1 P D 2258 く2 < 0.0968 0.23:58) PC Pl Z S-O0968 O-N 0.461443- O.410678 11 (3-1)2 I54 =O.0624O v(M)= 1 N (72, 0.06240) < 71-1) 71-7-72 0.2498 <m32 71-3-72 0.2498 <m D.2498 71-3 - 200) -2.802 s- 2-tor) <2009) P ZS 14 O.12356 0.002539 O.114895 mニ178 2) p- 0.52 nackhm meup Hore Qut as100 vatrs 52 Mimee duchric Joea dushricd nus duppert veters seLtg B LI 52 x118 (00 mean D.52 100 17 Mandard eror 6.SLX0-42 00374 11

274 7 153 EM 238.9 6.0391 JiS3