Question

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-14. Determine the electron geometry (eg) and molecular geometry (mg) of CH3-1. A) eg-tetrahedral, mg etrahedral B) eg-tetrahedral, mg-trigonal pyramidal C) eg-trigonal planar, mg-bent D) eg-trigonal planar, mg-trigonal planar E) eg tetrahedral, mg=trigonal planar -115. Draw the Lewis structure for CH4, what is the hybridization on the C atom? A) sp B) sp3 C) sp2 D) sp3d E) sp3d2

Answer 1

Answer(A): ^Eg tetrahedral Mg Tetrahedral There are 4 electron pair around central carbon atom. Therefore the electron pair arrangement of CH_3 is tetrahedral since CH_3 has no lone pairs the arrangement of bending pairs is same as that of the electron pair arrangement Lowis structure of CH_4 rightarrow H H C H H Answer option B (SP^3) Triploe bond implies double)c = c) single (c-c) (order of bond strength) Bond length depend on bond strength the stronger the bond is the shorter it will be order of bond length Triple bond (c = c) double (c = c) < single (c-c) Answer option D, Weakest longest Na^+ [cl] delta H for which reaction(specify the reaction)