Question

Determine the electron geometry (eg) and molecular geometry (mg) of the underlined atom CH3OCH3.

Answer options:
eg=trigonal bipyramidal, mg=tetrahedral
eg=linear, eg=linear
eg=tetrahedral, mg=tetrahedral
eg=tetrahedral, mg=bent
eg=octahedral, mg=square planar

Answer 1

The electron domine around the carbon 1 is 4 (four bonding). Therefore, electron geometry and molecular geometry is tetrahedral Around Cl: eg tetrahedral mg - tetrahedral The electron domine around the oxygen atom is 4 (two bonding and two non bonding). Therefore, the electron geometry around oxygen is tetrahedral and molecular geometry is Bent. Around O: eg tetrahedral mg Bent The electron domine around the carbon 1 is 4 (four bonding ). Therefore, electron geometry and molecular geometry is tetrahedral. Around C2: eg tetrahedral mg tetrahedral

Answer 2

. There
are two compounds that correspond to this formula: ethyl alcohol and dimethyl ether. While the
molecular formula gives no clue as to which compound one may be referring, examination of the
structural formula immediately reveals a different arrangement of atoms for these substances:
H H H H
? ? ¦ ¦
H —C—C—O—H H—C—O—C—H
¦ ¦ ¦ ¦
H H H H
Ethyl alcohol Dimethyl ether


and the eg=tetrahedral mg=bent

Answer 3

Both carbons are sp hybridized. Hence the correct answer is tetrahedral, tetrahedral.