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Homework Answers
When S2 is closed , inductor is short circuited means potential across inductor is zero .
As R1 and R2 are in series equal current passes through both.
on applying Kirchoff's law :-
E-I(R1+R2)=0
I=E/(R1+R2)=50/(2+3)=50/5=10A
Hence, current through R2 when switch S2 is closed is 10A.
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