Question

A sphere of radius r = 34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0° incline that is
Part B Calculate its rotational speed when it reaches the bottom. Express your answer using three significant figures and inc
Part D Avoid putting in numbers until the end so you can answer: do your answers in previous parts depend on the radius of th
0 0
Add a comment Improve this question Transcribed image text
Answer #1

h = 10sm 30 = 5m u ^) 5) w- Energy conservation I = I onih - Ist + im ta migh vow 한 쁖 일는 mg + V² + 1 v² gh vough - 24.845 18:

Add a comment
Know the answer?
Add Answer to:
A sphere of radius r = 34.5 cm and mass m = 1.80 kg starts from...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest...

    A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0? incline that is 10.0m long. Part A Calculate its translational speed when it reaches the bottom. v= Part B Calculate its rotational speed when it reaches the bottom. Express your answer using three significant figures and include the appropriate units. w = Part C What is the ratio of translational to rotational kinetic energy at the bottom?...

  • A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0° incline that is 10.0 m long.

    A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0° incline that is 10.0 m long.A) Calculate its translational speed when it reaches the bottom.B) Calculate its rotational speed when it reaches the bottom.      C) What is the ratio of translational to rotational kinetic energy at the bottom?        D) Avoid putting in numbers until the end so you can answer: do your...

  • A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest...

    A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0∘ incline that is 10.0 m long. Calculate its translational speed when it reaches the bottom. Calculate its rotational speed when it reaches the bottom. What is the ratio of translational to rotational kinetic energy at the bottom?

  • A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest...

    A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0∘ incline that is 10.0 m long. Calculate its translational speed when it reaches the bottom. Calculate its rotational speed when it reaches the bottom. What is the ratio of translational to rotational kinetic energy at the bottom?

  • A uniform, solid sphere of radius 4.00 cm and mass 2.00 kg starts with a translational...

    A uniform, solid sphere of radius 4.00 cm and mass 2.00 kg starts with a translational speed of 2.00 m/s at the top of an inclined plane that is 1.00 m long and tilted at an angle of 20.0° with the horizontal. Assume the sphere rolls without slipping down the ramp. 1) Calculate the final speed of a solid sphere. (Express your answer to three significant figures.)

  • Q10 A hollow sphere and a hoop of the same mass and radius are released at...

    Q10 A hollow sphere and a hoop of the same mass and radius are released at the same time at the top of an inclined plane. If both are uniform, (1) Which one reaches the bottom of the incline first if there is no slipping? (2) A uniform hollow sphere of mass 120 kg and radius 1.7 m starts from rest and rolls without slipping dow an inclined plane of vertical height 5.3 m. What is the translational speed of...

  • thank you Problem 5 A solid sphere of mass M-2.00 ks (uniformly distributed) and radius R...

    thank you Problem 5 A solid sphere of mass M-2.00 ks (uniformly distributed) and radius R -0.100 m starts from rest at the top of an inclined plane of length L - 1.50 m and height H-0.500 m. The coefficient of static friction between the sphere and the inclined plane is H, -0.400. The sphere rolls without slipping down the inclined plane. The moment of inertia of the sphere about an axis through its center of mass is given by...

  • ran A disk of mass M and radius R has a hole of radius r centered...

    ran A disk of mass M and radius R has a hole of radius r centered on the axis. Calculate the moment of inertia of the disk. Express your answer in terms of the variables M, R, and r. 1= {M(R? +-2) Submit Previous Answers ✓ Correct Part B A 5.0-cm-diameter disk with a 3.0-cm-diameter hole rolls down a 55-cm-long, 21° ramp. What is its speed at the bottom? Express your answer to two significant figures and include the appropriate...

  • Review A disk of mass M and radius R has a hole of radius centered on the axis. Part A Calculate the moment of inertia...

    Review A disk of mass M and radius R has a hole of radius centered on the axis. Part A Calculate the moment of inertia of the disk. Express your answer in terms of the variables M, R, and T. VALD O2 ? MR2 mR 22 Submit Previous Answers Request Answer Part B A 5.0-cm-diameter disk with a 3.0-cm-diameter hole rolls down a 55-cm-long, 21 ° ramp. What is its speed at the bottom? Express your answer to two significant...

  • Problem 7.79 14 of Con A block of mass m = 3.00 kg starts from the...

    Problem 7.79 14 of Con A block of mass m = 3.00 kg starts from the rest and slides down a 30.0° incline which is 3.60 m high. At the bottom, it strikes a block of mass M = 8.00 kg which is at rest on a horizontal surface (Figure 1). (Assume a smooth transition at the bottom of the incline.) The collision is elastic, and friction can be ignored. Part A Determine the speed of the block with mass...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT