Question

We would like to estimate the true proportion of all Winnipeggers who read the Winnipeg Free...

We would like to estimate the true proportion of all Winnipeggers who read the

Winnipeg Free Press. What sample size is required to estimate this proportion to

within 0.03 with 88% con dence?

(A) 612

(B) 632

(C) 672

(D) 652

(E) 692

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Answer #1

Here we have to find the sample size for margin of error E= 0.03 and confidence level c = 0.88

For c = 0.88 table value Zc = 1.555

so, sample size is given by,

m = 0.5 +0.5*(三)

1.555 2 n = 0.5 * 0.5 * ( 0,03

n = 671.6736

m = 672

Answer: c) 672

.09 5239 .5753 6141 6517 6879 7224 7549 7852 8133 R299 8621 .8830 9015 9177 9319 041 .9545 633 9706 .9767 9817 8485 .9082 909

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