Question

You might need: Calculator Keita left camp three days ago on a journey into the jungle. The three days of his journey can be described by displacement (distance and direction) vectors dı, de, and ds. di = (7,8) de = (6,2) d3 = (2,9) (Distances are given in kilometers, km.) How far is Keita from camp at the end of day three? km (Round your final answer to the nearest tenth.) What direction is Keita from camp at the end of day three? Assume 0 is the rightward direction. (Round your final answer to the nearest degree. Your answer should be between 0 and 180°)

Answer 1

BY THIS WAY, ANSWER OF GIVEN PROBLEM.

od Here, TET.EEX di = (7,8), dr = (6,2) a} = (29) Final Displacement, so, = (di + d2 + de +9) 7+6+2, 8+2 5 ( 15 29). I 17) - Va58 +(29) - 24.2 km (ii) tamo i - y tano = (1915) 0 =51.770 L 6 Keita is 24.2km far at the end of Three & 4 Direction is 51.75 to x-axis