Question

Part I

I would like to know if the following molecule is "meso". Could you please provide an explanation why it is or why it is not?

CI -CI

Part II

I was asked to analyse what the product of the following reaction is.

I know that the right answer is the following:

What I would like to know is what rule determines that the methyl group will most likely be connected to the carbon that is connected to the benzene molecule; and that - as a secondary option - it can be located on a carbon that it located next to the carbon that is connected to the benzene molecule (as shown on the picture). What is the rule/logic?

Thank you!

Answer 1

the given reaction is a electrophilic aromatic substitution reaction the more stable carbocation is attack on benzene is major product

part-1 it is meso compound, * 2 Lu * A meso compound hat at least two Stereo centers (e, and (s) but is not chired due to an axis of Symmetry Barch of the given molecule have Two Stereocauters. meso compound because they have an Internal mirror plane passing through Ca and The Mid point of The C1-C, band. * If you cut the molecule get noo Identical half molecule. parken Major Minor. it is a electrophilic Aromatic Substitution Reaction <A H-shift و دبل) معمایی socarbocation in Tus Alkylation Reaction 29 Carbocation and go carbocation Intermediate is formed, 30 cambocahian is more stable so the resultant product attack of 3o cambrication to bemaene is major product Major product