Question

ly assigns. 50 participants to one of two groups (25 in each group). One assessed. 11. Write a rescarch hypothesis and null hypothesis for Dr. Cunningham's research. Ho : 12. What statistical test should Dr. Cunningham use to test his hypothesis? (be specific) 13. Dr. Cunningham replicates and extends his experiment. This time he uses three groups, one receives the new memory intervention, one receives relaxation training, and one does not receive any intervention. He then tests their memory. What statistical test should Dr. Cunningham use to test the differences between the groups? 14. Dr. Cunningham again replicates and extends his experiment. He creates the same three groups did in the previous research but this time he tests their memory right after the intervention/trair and then again a week later. Using the following information to answer questions 15-18 t(28)-2.56, p .02 Group 1: M 4.3, SD 1.3 Group 2: M 3.2, SD 1.4 15. Group 1 is not significantly different than Group 2? Yes No 16. Group 2 is significantly larger than Group 1? Yes No 17. Group 1 is significantly larger than Group 2? Yes No 18. Group 2 is significantly different than Group 1? Yes No

Answer 1

Solution:-

15) No, Group 1 is not significantly different than group 2.

Null hypothesis: u₁ = u ₂
Alternative hypothesis: u₁ $\neq$ u ₂

Note that these hypotheses constitute a two-tailed test.

Since p-value(0.02) less than 0.05, hence we have to reject the null hypothesis.

16) No, The group 2 is significantly larger than group 1.

Null hypothesis: u₁ = u₂
Alternative hypothesis: u₁ > u₂

Note that these hypotheses constitute a one-tailed test.

Since p-value(0.99) less than 0.05, hence we have to reject the null hypothesis.

17) Yes, The group 1 is significantly larger than group 2.

Null hypothesis: u₁ = u₂
Alternative hypothesis: u₁ > u₂

Note that these hypotheses constitute a one-tailed test.

Since p-value(0.01) less than 0.05, hence we have to reject the null hypothesis.

18) Yes, Group 1 is not significantly different than group 2.

Null hypothesis: u₁ = u ₂
Alternative hypothesis: u₁ $\neq$ u ₂

Note that these hypotheses constitute a two-tailed test.

Since p-value(0.02) less than 0.05, hence we have to reject the null hypothesis.