horizontal distance x= horizontal velocity * time taken
x = 13.2*cos(54)*T
T is the time of flight
using the equation s = (uy*t)- (0.5*g*T^2)
-1.6 = (13.2*sin(54)*T)-(0.5*9.81*T^2)
T = 2.32 s
then x = 13.2*cos(54)*2.32 = 18 m
So the required distamce is d = 18-14 = 4 m
Part B Question 8 In the middle of the night you are standing a horizontal distance...
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