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An object with mass m1 = 3.56kg .... please answer parts a-c !!! please show work. Thank you!
v= 1. An object with mass ml = 3.56 kg, moving on a frictionless surface with a velocity of +2.50 m/s to the right, collides
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Answer #1

As law per of Consevation of momentum, mi4,+ m₂ 42 = m, o,+ m₂ 3,56x 2,5+2.75x-1.35 = 3.56*-0.74 +2.75 V2 - U₂ = 2.844 m/ nee

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