Question

d. Assuming the diode 1N4148 is ideal with built-in potential approximately 0.7V, calculate the period of the modified relaxation oscillator in Fig. 7 and also sketch the theoretical vet) and Vout(t).

Vsat+ = 8V and Vsat- = -8V

Answer 1

Given circuit & out TomF 25kr vse loka

given tsat = 8v - usat =-84 Case IH then Vout = + sat = 8 Nae= 10 x vout 10+25 so vre= 10 x8 35 voltage source - tle) vre = 2.285v! and Dzis forward biased but Di 18 reversed biased. That's why capacitor will charge upto wre voltage. Here diis replaced by 0-7v so velti = (8-0-3 (1- ě so vecto= 7.3 (1- ě tla here I= R36 = 100x103x10x15 Zo 10-3 sec. so valt) = 73 (-ė 1000t) at vects = va so 7-3 (1-é 1000ty) = 2.285 so - é 1000t = 0.313 or e loroti zn. or -1000 tia enco-G87) tlvrot i= ato.3754 so ti= 0.3754x16 33 so t= 6.3754ms Caseting - If then Nout=-usat=-8v use = 10 x vout= 042s 10 x- 35

so vre=-2.285v I Here D2 will be forward based but piis reversed blased so here capacitor will discharge upto vse. we know that volto= Vocool + [veco)-vecool here Vecco = -7.3V Vcco)= 2.285 so valt) = -7.3+( 2-285-(-7.33) velte E-73+9.585e-tie here TERUS = 16X1000 X 10X16 - so I=154 sec. or vects = -7.3+ 9.585 e at vre= -2.285= vouclts - -10422 so -2.285=-2-3+9.585 éto so g. 585ě 10422 = 5.015 or e-104t2= 0.5232 or -104t2= ln (65232) +104+z= +0.6477 - orlt2 = 0.06477ms! So waveforms will be- voutit) Lovelt) 228547 m At titta Hitta +2. 285v

So time periode (T) = tittz So I=0-3754to-osuz IT-0.44017 ms Please like my solutions