Question

H2O(I)>NH3(g)+LiOH(ag)?

determine the mass of lithium hydroxide produced when 0.38 grams of lithium nitride reacts with water according to the following unbalanced chemical equationLi3N(s)+H20(I)>NH3(g)+LiOH(ag) ?

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Answer #1
The balanced Equation is :Li3N(s) + 3H2O(l) -----> NH3(g) + 3LiOH(aq)Molar mass of Li3N is = (3x6.94) + 14 = 34.82 g/molMolarmass of LiOH is = 6.94 + 16 +1 = 23.94 g/molAccording to the balanced chemical Equation ,34.82 g of Li3N produces 3x23.94 = 71.82 g of LiOH0.38g of Li3N produces X g of LiOHX = ( 0.38 x 71.82 ) / 34.82= 0.78 g of LiOH
answered by: Aha
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