The following function prints a natural number sequence across the diagonal of an n by n square matrix. Debug the code to fix all the compilation and run-time errors, so that the code generates the desired output. For instance, when the num value passed to the function is 5, the output would look like the following.
1****
*2***
**3**
***4*
****5
void naturalDiagonal(int num);
for (int i=0; i < num - 1; i++)
{
for (int j=1; j <= number; j++)
{
if i == j-1
{
cout << i;
}
else
{
cout << "*";
}
cout << endl;
}
}
}
please find the final code
void naturalDiagonal(int num){
for (int i=0; i < num - 1; i++)
{
cout << endl;
for (int j=1; j <= num; j++)
{
if (i == j-1)
{
cout << i;
}
else
{
cout << "*";
}
}
}
cout<<endl;
}
i have made below changes
1) for (int j=1; j <= number; j++) is changed to for (int j=1; j <= num; j++)
2) added a new cout statement at the second last line
3) also added cout<<endl; after the first for loop
The following function prints a natural number sequence across the diagonal of an n by n...
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