Show that hydrogen peroxide (H2O2) is a liquid at 25°C by using the data below. ΔHf°...
Show that hydrogen peroxide (H2O2) is a liquid at 25°C by using the data below.
ΔHf° (kJ mol-1) data: H2O2(l) = –187.8; H2O2(g) = –136.3
So (J mol-1 K-1) data: H2O2(l) = 110; H2O2(g) = 233
Homework Answers
H2O2 (l) -----------> H2O2 (g)
ΔH°rxn = ΔHf° products - ΔHf° reactants
= - 136.3 - (- 187.8)
= 51.5 kJ
ΔSorxn = 233 - 110
= 123 J/K
ΔGo = ΔH - T ΔS
0 = ΔH - T ΔS
T = ΔH / ΔS = 51500 / 123
T = 418.7 K
boiling point = 145 oC
the estimated boiling point is more than room temperature. so
this is liquid .
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Show that hydrogen peroxide (H2O2) is a
liquid at 25°C by using the data below.
ΔHf°...
Hydrogen peroxide, H2O2, is a colorless liquid whose solutions are used as a bleach and an...
Hydrogen peroxide, H2O2, is a colorless liquid whose solutions are used as a bleach and an antiseptic. H2O2 can be prepared in a process whose overall change is H, O2 (1) H2(g) +O2(g) Calculate the enthalpy change using the following data: 2H2O2()2H2 O (l) + O2(g); AH = -196.0 kJ H2(g) +O2(g)H2O(); AH= -285.8 kJ ΔΗ- kJ 10 item attempts remaining Try Another Version Submit Answer
Please help me solve this problem. 8.) Given the following table of thermodynamic data, Substance AHf...
Please help me solve this problem.
8.) Given the following table of thermodynamic data, Substance AHf (kJ/mol) | Sº (J/mol · K) H2O2 (g) 232.6 H2O2 (1) -187.8 110 -136.3 Find the value of K for the vaporization of H202 (1).
72. Hydrogen peroxide is a very common oxidizing agent. It has been used as an oxidizer...
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21.The temperature at which the following process reaches equilibrium at 1.0 atm is the normal boiling point of hydrogen peroxide. H2O2(1) H2O2(g) Use the following thermodynamic information at 298 K to determine this temperature. Substance AH°F (kJ mol-)) AG°f (kJ mol Sº (J K-mol) H2O2(1) -187.7 -120.4 109.6 H2O2(g) -136.3 -105.6 232.7 B. 691 K C. 469 K D. 144 K A. 418 K E. 393 K
Exam Hydrogen peroxide, H202, is a colorless liquid whose solutions are used as bleach and an...
Exam Hydrogen peroxide, H202, is a colorless liquid whose solutions are used as bleach and an antiseptic. H2O2 can be prepared in a process whose overall change is H2(g) + O2(g) -H02(1 Calculate the enthalpy change using the following data: H2O2(1) - H20(1) +502 (8); AH = -98.0 kJ (1) 2H2(g) + O2(g) → 2H20(1): AH = -571.6 kJ (2) 5. What is the wavelength, in nanometer, of light emitted when the electron in a hydrogen atom undergoes a transition...
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Be sure to answer all parts. Liquid hydrogen peroxide, an oxidizing agent in many rocket fuel...
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Hydrogen peroxide, H2O2, is a colorless liquid whose solutions are used as a bleach and an antiseptic. H2O2 can be prepared in a process whose overall change is H, O2 (1) H2(g) +O2(g) Calculate the enthalpy change using the following data: 2H2O2()2H2 O (l) + O2(g); AH = -196.0 kJ H2(g) +O2(g)H2O(); AH= -285.8 kJ ΔΗ- kJ 10 item attempts remaining Try Another Version Submit Answer
Please help me solve this problem.
8.) Given the following table of thermodynamic data, Substance AHf (kJ/mol) | Sº (J/mol · K) H2O2 (g) 232.6 H2O2 (1) -187.8 110 -136.3 Find the value of K for the vaporization of H202 (1).
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Liquid hydrogen peroxide is an oxidizing agent in many rocket fuel mixtures because it releases oxygen gas on decomposition as shown below. 2 H202 (1) ► 2 H20,() + O2 (g) AHrxn = -196 kJ How much heat istreleased when 25.0 grams of H202 decomposes? Molar Mass(H2O2) = 34.01 g/mol Ca.-133 kJ b.-533 k] c-72.0 kj 0-288 kJ e-144 kJ
How is A the answer?
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