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10.02 m a 0.2 H s 000 5) Consider the circuit in the figure. For a long time prior to time t=0, the switch is in position a,
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, E-12.0v R-1002 - 2.0MF L-0.2H emf of battery Resistance Capacitance inductance. Now T = RC I- 10.08 2.04 106 I=20.0x10 6 5(b since at to switch is at position a so chara Oace -2.0 x10x Q = 24.0 mc (c) enugy stored is CE2 1 x2:0x10** (12.0) 144.0x4 parts done as per HomeworkLib guidelines.

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