A substance (A) reacts to form another substance (B): 3A(g) --> 2B(g) The reaction is run...
help me pleaseee Question 24 (1 point) A substance (A) reacts to form another substance (B): 3 A(g) = 2 B(8) The reaction is run at a particular temperature with the concentrations of A and B monitored over time and plotted in the graph. At what time was equilibrium first reached and what is the approximate value of the equilibrium constant? 2.0 16 IR [B] concentration/M 10 08 0.6 0.4 0.2 0.0 0 [A] 10 20 60 70 80 90...
please help as soon as possible ergent Question 24 (1 point) A substance (A) reacts to form another substance (B): 3 A(9) 2 B(9) The reaction is run at a particular temperature with the concentrations of A and B monitored over time and plotted in the graph. At what time was equilibrium first reached and what is the approximate value of the equilibrium constant? 2.0 16 [B] LO concentration/M 10 IA] 04 00 • 30 20 x 50 60 90...
For the reaction 3A(g)+2B(g)⇌C(g) Kc = 92.6 at a temperature of 271 ∘C . Calculate the value of Kp
For the reaction 3A(g)+2B(g)⇌C(g) Kc = 73.0 at a temperature of 379 ∘C . Calculate the value of Kp. Express your answer numerically. For the reaction X(g)+2Y(g)⇌3Z(g) Kp = 2.82×10−2 at a temperature of 195 ∘C . Calculate the value of Kc. Express your answer numerically.
1. The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)Δn where R=0.08206 L⋅atm/(K⋅mol), T is the absolute temperature, and Δn is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)⇌2NH3(g) for which Δn=2−(1+3)=−2. Part A For the reaction 3A(g)+2B(g)⇌C(g)...
At a certain temperature, this reaction establishes an equilibrium with the given equilibrium constant, Ke! 3A(g) +2B(g) = 40() K.=2.13 10" Wat this temperature, 1.90 mol of A and 3.60 mol of B are placed in a 1.00-L container, what are the concentrations of A, B, and C at equilibrium? Number (A)- O M Number Number (c)-
the question is " 3A + 2B --><--4C with Kc=1.73x10^23, if at this temperature 1.00 mol of A and 3.70 mol of B are placed in a 1.00 L container, what are the concentrations of A,B, and C at equilibrium?" this is my work so far, I am not sure how to go further. placed incl.ool at equilibrium? 4C 14 3A (g) + 2B (g) 2 ucco Kca 1.73 x 1033 Ip at this temp 1.oom of b and 3.70mol...
5. The equilibrium constant, KcKc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, KpKp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)Δn where R=0.08206 L⋅atm/(K⋅mol)R=0.08206 L⋅atm/(K⋅mol), TT is the absolute temperature, and ΔnΔn is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)⇌2NH3(g) for which Δn=2−(1+3)=−2 For the reaction 3A(g)+2B(g)⇌C(g) KcKc...
The reaction NO_2 (g) + NO (g) doublesidearrow N_2O (g) + O_2 (g) reached equilibrium at a certain high temperature. Originally, the reaction vessel contained the following initial concentrations: 0.184 M N_2O, 0.377 M O_2, 0.0560 M NO_2 and 0.294 M NO. The concentration of NO_2, the only colored gas in the mixture, was monitored by following the intensity of the color. At equilibrium, the NO_2 concentration had become 0.118 M. What is the value of Kc for the reaction...
For the reaction 3A(g) + 2B(g) → 2C(g) + D(g) the following data was collected at constant temperature. Determine the correct rate law for this reaction. run [A] (M) [B] (M) Rate (M/s) 1 . 0.125 0.200 7.25 2 0.375 0.200 21.75 3 0.250 0.400 14.50