Question

last 3 digit are 072 so the sum of the ID is 9

The truss shown is made from thee rods that have the same cross-sectional area and elastic modulus (E). The rods are pinned at the three supports as shown. If the top node was pulled horizontally by a distance 8, 1) Find the horizontal force that should be applied at the top node to move it horizontally by 8. 2) Determine the vertical displacement of the top node Note: solve this problem by hand (you can use symbolic toolbox to assist you) Note: the angle 0 is equal to the sum of the digits making your / S ID number 8 LI 0 90-0

Answer 1

please find the below solution
Let E, A are youngs Madeleung x croge sectional crea of 3 rodę. 2 a3 2 8 Given 3 2 T BOC qi q7 fram s123, eel D 0.974 6.18 -0.979 618 GIVEN 0-90 23=S. 90-e lez=l. 90-0 180.0 from 2 34 D art 3 98. 96 Sincceiro = lez 고 e 95 dez sinol = 0856l. sin (90-0) = dea le = 0.1561 -0.158 1 Cosa LE Cose, = Cos (400)= sina=0.156 dy = 659050 mi - Sino, = sin(90-0) = cos 9 = 0.988 - Singo - 1 ez = cos C180-0) = -lose =-0.988 m3= Sir (180-0) = sinq = 0.156. 92 24 K = EA fo: 0243 0.158 20-028-01 lon r12 com EA de lo 10.154 08.476 40:154 - 12 lm lon -0/0243 -0.154 oot -hm loon 20-1.50 -0.976 243 KE aus -0.05 0.0243 0.134 92 93 qq -0.154 0.159 0.974 -0.154 den 01581 q 0.154 -0.159 -0.976 0.0743 60159 100243 0.159 +8 159 - 0974 0154 0974 -0.154 -0.976 0156 0.976 -0.979 -6-18 0.974 618 CSScanned with camScanner m2 an q3 2 22 019 2028 4 m2 - lm rm2 -0.97€ 12 - EA 0.976

az qq ar a -- o o Ky - EA 0.1561 0 E 6:41 0 -6.4) e o 10 -641 6.41 98 ut aaias o 154 l -0.976 az aq 97 - EA 0.976 0.154 -0.159 0.0243 olsa rao2a3 -0.159 Lo to 154 0.0273 Global Stifreey matina Kakitketky Goreing equat Ko=f 0.154 0.976 0.154 V00293 1 4 2 B & 5 6 7 8 8.154 0.979 -0.154 -0.974 q -) 6.18 -0.979 -6-18 o 0.974 -0.156 -0.974 -618 1.13 0.82 -0.976 0.154 a3 EA|-0.979 1760154 fyzo Eza fyra 0.82 12.619 ł -6.41 0159 *0.0243 | 24 0 O O -6.41 0 -0.976 0. 154 0 6.41 0.976 -0.154 0 -0.154 0.0243 as fx so 26 |fzy to Fap To (as) (feyro O 197 o O 0.154 -0.0193 By boundary we came to know 9, 742 = US == 4 =Cio eliminate 1, 2,5, 6, 6,7;8 sowe & Columns = EA aa ใน 1.13 0.82 193=8 fra l 0.82 12.614) La O CSScanned with CamScanner

(1-138 +0.82 .24) = 624 o ㅈ 0.828 + 12.614 qq co 29 - -0.828 %2-8 Displacement at vertical Displacement 12-619 % = -0.0658 nade Top EA 1-138 + 0.82 -0.0658) fey e = EA (1.0776) is the applied force at Ex d ncole 2 in 1 B direction CSScanned with CamScanner