Z critical value for 99% confidence level is 2.5758 (by using Z table) or =NORMSINV(1-(0.01/2))
Confidence interval formula
=>(-0.0288,0.2288)
Therefore, 99% confidence interval is (-0.0288, 0.2288)
Consider the following data from two independent samples. Construct a 99% confidence interval to estimate the...
are my answers correct? Consider the following data from two independent samples with equal population variances. Construct a 99% confidence interval to estimate the difference in population means. Assume the population variances are equal and that the populations are normally distributed x1 = 67.9 s1 = 12.8 n1 = 10 X2 74.8 s2 = 8.1 n2 = 14 Click here to see the t-distribution table, page 1 Click here to see the t-distribution table,_page 2 The 99% confidence interval is...
Consider the following data from two independent samples with equal population variances. Construct a 99% confidence interval to estimate the difference in population means. Assume the population variances are equal and that the populations are normally distributed. x overbar 1 equals= 37.1 x overbar 2 equals= 32.8 s 1 equals= 8.68 S2 equals= 9.59 N1 equals= 15 N2 equals= 16 The 99% confidence interval is ( )(. ).
Consider the data to the right from two independent samples. Construct a 90 % confidence interval to estimate the difference in population means.Click here to view page 1 of the standard normal table. LOADING... Click here to view page 2 of the standard normal table. LOADING... x overbar 1 equals 43 x overbar 2 equals 51 sigma 1 equals 10 sigma 2 equals 14 n 1 equals 35 n 2 equals 40 The confidence interval is left parenthesis nothing comma...
X11.1.15 Construct a confidence interval for p - p2 at the given level of confidence. X1 28, n1 236, x2 40, n2 308, 99% confidence % confident the difference between the two population proportions, p - P2. is between The researchers are and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)
Consider two independent random samples with the following results: n1=123pˆ1=0.48 n2=367pˆ2=0.63 Use this data to find the 80% confidence interval for the true difference between the population proportions. Copy Data Step 1 of 3 : Find the point estimate that should be used in constructing the confidence interval. Step 2 of 3: Find the value of the margin of error. Round your answer to six decimal places. Step 3 of 3: Construct the 80% confidence interval. Round your answers to...
Construct the indicated confidence interval for the difference between population proportions p1- P2. Assume that the samples are independent and that they have been randomly selected. X1 = 19, n1 = 46 and x2 = 25, n2 = 57; Construct a 90% confidence interval for the difference between population proportions P1 - P2. A) 0.252 < P1 - P2 < 0.574 OB) 0.221 < P1 - P2 < 0.605 C) 0.605 < P1 - P2 < 0.221 OD) -0.187 <...
Construct a 99% confidence interval to estimate the population mean using the data below. X = 46 o = 12 n42 With 99% confidence, when n = 42 the population mean is between a lower limit of (Round to two decimal places as needed.) and an upper limit of Construct a 95% confidence interval to estimate the population mean with X = 102 and o = 25 for the following sample sizes. a) n = 32 b) n = 45...
11. Construct the indicated confidence interval for the difference between population proportions. Assume that the samples are independent and that they have been randomly selected. A marketing survey involves product recognition in New York and California. Of 558 New Yorkers surveyed, 193 knew the product while 196 out of 614 Californians knew the product. Construct a 99% confidence interval for the difference between the two population proportions. 12. Construct the indicated confidence interval for the difference between population proportions. Assume...
Consider the following results for independent samples taken from two populations. Sample 1 Sample 2 n1 = 500 n2 = 200 p1 = 0.47 p2 = 0.33 a. What is the point estimate of the difference between the two population proportions (to 2 decimals)? b. Develop a 90% confidence interval for the difference between the two population proportions (to 4 decimals). to c. Develop a 95% confidence interval for the difference between the two population proportions (to 4 decimals). to
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 90% confidence interval estimate for the difference between the two population means. n1 = 17 x1 44 n2 13 x2 = 49 The 90% confidence interval is s(uI-12) (Round to two decimal places as needed.) «D