Question

2. At standard temperature and pressure, 5.6 L of H,S is dissolved in enough water to produce 2.50 L of solution. Calculate the pH of this solution and percent ionization of H,S.

Answer 1

By using ideal gas equation we can calculate number of moles of tas gas- PU=nRT at standard Condition p=latm v =5.6 lt of bbs gas na no of molet R = ideal gas constant = 0.0821 Hatme mol- t=213k .. (1) (5:6)n (0.0821) (273) 0.25 moles na 5.6 10.0821)(273) in water to 0.25 moles of the gas is dissowed produce 2.5 14 Solution. moles = Concentration Volumel) 0.1 M. 0:25 = 2.5

By using ICE table for Has H₂S + H2O & H5 + H₂ot I 0.1 - 0 0 te c -X the How ol-2 - Ka= (x)(2) 10 К &ov , s = 9.5x108 ka is very small, so n is also very smell, we consider oil-e a on 4.5x18 = 9 ve 0.95x108 a = 10.95xiole = 0.97 x70" From ICE table, That] or [ht] = 0.978104

(16 ۵۰۹۹x) وما = [y وم- : م 0 . 497) و0+ (1) وما ] .: [50513 - (۱) ؟ - - 37ره . ا - - = 013. ما = m [1] X 100 ionisation = % لكي - X100 0:41x1o 0.094 / =