An ISP granted a block of addresses starting with 192.168.0.0/20. The ISP need to distribute these...
An ISP granted a block of addresses starting with 192.168.0.0/20. The ISP need to distribute these addresses to three groups of customers as follow:
• The first group has 32 customers, each needs 64 addresses.
• The second group has 16 customers, each needs 32 addresses.
• The third group has 16 customers, each needs 128 addresses.
Design the sub-blocks for the above given specifications.
Homework Answers
Answers:
For First Group:
Given that each customers needed 64 addresses, So the suffix length is 26=64 i.e 6. Therefore prefix length will be 32-6=26.
The address will be
| 1st customer | 192.168.0.0/26 | 192.168.0.63/26 |
| 2nd customer | 192.168.1.0/26 | 192.168.1.63/26 |
| 3rd customer | 192.168.2.0/26 | 192.168.2.63/26 |
| . | . | . |
| . | . | . |
| . | . | . |
| upto 32th customer | 192.168.31.0/26 | 192.168.31.63/26 |
For 2nd Group
Given that each customers needed 32 addresses, So the suffix length is 25=32 i.e 5. Therefore prefix length will be 32-5=27.
The addresses are:
| 1st customer | 192.168.32.0/27 | 192.168.32.31/27 |
| 2nd customer | 192.168.33.32/27 | 192.168.33.128/27 |
| 3rd customer | 192.168.34.32/27 | 192.168.34.128/27 |
| . | . | . |
| . | . | . |
| . | . | . |
| upto 16th customer | 192.168.47.32/27 | 192.168.47.128/27 |
For 3rd Group
Given that each customers needed 128 addresses, So the suffix length is 27=128 i.e 7. Therefore prefix length will be 32-7=25.
The addresses are:
| 1st customer | 192.168.48.0/25 | 192.168.48.127/25 |
| 2nd customer | 192.168.49.128/25 | 192.168.49.128/25 |
| 3rd customer | 192.168.50.128/25 | 192.168.50.128/25 |
| . | . | . |
| . | . | . |
| . | . | . |
| upto 16th customer | 192.168.64.128/25 | 192.168.64.128/25 |
Finally Sub blocks diagram
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