Given equation
Sinx=√2/2=1/√2
For x=45°
We have, Sin45°=1/√2
Since ; Sin(180°-x)=Sinx
Therefore, Sin(180°-45°)=Sin(135°)=Sin45°
Sin135°=1/√2
Answer:- x=45° , x=135° is the required value of x between 0° to 360°
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