According to law of conservation of angular momentum, aroud a planet
Here r1= 6400+225 =6625km
and v1 = 9.85km/s
therefore r2 = 6400+ha , here 6400km is the radius of the earth
NOTE: in the given data the velocity at apogee is missing, when you substitue we get ha.
A satellite is put into an elliptical orbit around the Earth. When the satellite is at...
A satellite is put into an elliptical orbit around the Earth. When the satellite is at its perigee, its closest approach to the Earth, its height above the ground is hp = 217.0 km and it is moving with a speed of vp = 8.850 km/s. When the satellite reaches its apogee, at its farthest point from the Earth, what is its height ha above the ground?
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A satellite is put into an elliptical orbit around the Earth. When the satellite is at its perigee, its nearest point to the Earth, its height above the ground is hp=227.0 km, and it is moving with a speed of vp=8.950 km/s. The gravitational constant G equals 6.67×10−11 m3·kg−1·s−2 and the mass of Earth equals 5.972×1024 kg. When the satellite reaches its apogee, at its farthest point from the Earth, what is its height ha above the ground? For this...
A satellite is put into an elliptical orbit around the Earth. When the satellite is at its perigee, its nearest point to the Earth, its height above the ground is he = 227.0 km, and it is moving with a speed of up = 8.050 km/s. The gravitational constant G equals 6.67 x 10-'1 m² kg---5-2 and the mass of Earth equals 5.972 x 1024 kg. When the satellite reaches its apogee, at its farthest point from the Earth, what...
A satellite is put into an elliptical orbit around the Earth. When the satellite is at its perigee, its nearest point to the Earth, its height above the ground is ho = 207.0 km, and it is moving with a speed of v, = 8.050 kr/s. The gravitational constant G equals 6.67 x 10-11 m² kg-15-2 and the mass of Earth equals 5.972 x 1024 kg. When the satellite reaches its apogee, at its farthest point from the Earth, what...
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