Question

The equilibrium constant, Kp, for the following reaction is 0.160 at 298 K. Calculate K, for this reaction at this temperatur

The equilibrium constant, Kp, for the following reaction is 0.160 at 298 K. 

Calculate K, for this reaction at this temperature. 

2NOBr(g)  2NO(g) + Br2(g) 

Kc =

0 0
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Answer #1

Given reaction & NOB019) a NO(g) + B x (9) Kp = 0.16 at da8K. we know that I K = Kc CRYJAR An = [number of moles of gaseous pKc = . Kp (RT)An Kc = 0.16 (8-314x298) * = 0.16 - 2477-572 = 6.4579X1os = HE = 6. 46x105

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