Question

Calculate the position of the image Express your answer in centimeters to three significant figures. Constants An object 0.640 cm tallis placed 13.5 cm to the left of the vertex of a concave spherical mirror having a radius of curvature of 21.5 cm . 8'E cm Submit Request Answer Part B Calculate the size of the image Express your answer in centimeters to three significant figures. cm Request Answer Part C Find the orientation (upright or inverted) and the nature (real or virtual) of the image. The image is Please Choose

Answer 1

using sign of convention, Height of object = y = + 0.640 cm Object distance, S = -13.5 cm focal length, f = -R/2 = -21.5/2 f = -10.75 cm Image distance, Sprime = ? using Mirror formula, 1/f = 1/s + 1/s 1/sprime = 1/f - 1/s = s - f/fs sprime = fs/s - f = (-10.75)(-13.5)/-13.5 - (-1.75) Sprime = 145.125/-2.75 = -52.77 cm Sprime = -52.77 cm = > This is the image distance from the vertex of mirror to left upto three significant figure, Sprime = 52.8 cm \r\n Size of image Magnification = -sprime/s = yprime/y yprime = (-sprime/5)y = -(-52.8)/(-13.5) times 0.640 cm yprime = -2.50 cm So, Height of image is Vertical-bar y Vertical-bar = 2.50 cm \r\n orientation of image and its nature. Since size of image or theight of image is yprime = -2.50 cm This (-) Sign signifies that Image is inverted. Nature since real rays meet & image is formed so the image is Real
Answers

Part a) 52.8 cm

Part b) 2.50 cm

Part c) Real and Inverted.