As a 2.0-kg object moves from (11i-5j)m to (7i-8j)m, the constant resultant force acting on it is equal to (4i-3j)N. If the speed of the object at the initial position is 4.0 m/s, what is its kinetic energy at its final position?
As a 2.0-kg object moves from (11i-5j)m to (7i-8j)m, the constant resultant force acting on it...
As a 2.0-kg object moves from ~r1 = −7ˆi + 2ˆj m to ~r2 = 8ˆi + 4ˆj m, the constant resultant force acting on it is equal to F~ = 2ˆi − 3ˆj N. If the speed of the the object at the initial position is 4.0 m/s, what is its kinetic energy at its final position?
1. A Constant force pushes an object and speeds it up. The object moves from (6i - 8j + 4k)m to (11i - 5j + 4k)m. The net force acting on the object is (2i + 4j + 5k)N. What is the increase in it's kinetic energy, in J? So I found in the x direction to be 10 J and in the y direction to be 12 J. I ignored the work in the k direction as the object...
A 2.0-kg particle has an initial velocity of (Si-4) m/s, Sometime later, its velocity is 7i +3j assuming no energy is lost in the process? m/s. How much work was done by the resultant force during this time interval, b. 49 J c. 19 d. 53 J e 27
A force of 30 N accelerates a 2.0 kg object from rest for a distance of 3.0 m along a level, frictionless surface; the force then changes to 15 N and acts for an additional 2.0 m. (a) What is the final kinetic energy of the object? (b) How fast is it moving?
The only force acting on a 2.0-kg object moving along the x axis is shown. If the velocity Vx is +2.0 m/s at t = 0, what is the velocity at t = 4.0 s? +6.0 m/s +2.0 m/s +7.0 m/s +5.0 m/s +4.0 m/s
If a single constant force acts on an object that moves on a straight line, the object's velocity is a linear function of time. The equation v=vi + at gives its velocity v as a function of time, where a is its constant acceleration. What if velocity is instead a linear function of position? Assume that as a particular object moves through a resistive medium, its speed decreases as described by the equation v = vi-vx, where k is a...
2. At an instant when a 4.0-kg object has an acceleration equal to (5i + 3j) m/s^2 one of the two forces acting on the object is known to be (12i + 22j) N. Determine the magnitude of the other force acting on the object. a. 2.0 N b. 13N c. 18N d. 1.7N e. 20N
A force moves an object in the direction of the force. The graph shows the force versus the object's position (a) Find the work done when the object moves from 0 to 2.0 m. (b) If the mass of this object is 1.5 Kg and it started from rest find the final velocity at 2.0 m.
A 2.0-kg block slides down a frictionless incline from point A to point B. A force (magnit on the block between A and B, as shown. Points A and B are 2.0 m apart.If the kinetic A is 10 J, what is the kinetic energy of the block at B? O N e blo A. a. 27 J b. 20 J c. 24 J e. 37 J ower end supported by a horizontal surface. 13. A spring (k-600 N/m) is...
5) An object is moving to the left at constant velocity. A constant force to the left is now applied to the object. Which of the following is correct? A) The object continues to move to the left, and its speed increases. B) The object continues to move to the left with a constant speed. C) The object continues to move to the left, and its speed decreases. D) The object immediately stops and then begins moving to the right...