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As a 2.0-kg object moves from ~r1 = −7ˆi + 2ˆj m to ~r2 = 8ˆi...

As a 2.0-kg object moves from ~r1 = −7ˆi + 2ˆj m to ~r2 = 8ˆi + 4ˆj m, the constant resultant force acting on it is equal to F~ = 2ˆi − 3ˆj N. If the speed of the the object at the initial position is 4.0 m/s, what is its kinetic energy at its final position?

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