Question

the following is in java
find the errors and answer the question
what would the output be if the program was functioning and the following was entered
Obect-Orientated Programming Systems Languages Applications

import java. Scanner: public class LabProgram { public static String create acconym String usssPhrase) { string total Acronym: intji: total Asconym "" for (1 == 0; j <user Phrass.length); ++j1) { if (i= usesPhrase.length0 - 1) { if (i=0) if (user Phrase.charAt(1) >= 65 & userPhrase.charAt()=90) { totalAcronym += userPhrase.charAt(o: else if (Character is Whitespace(uses Phrase.charAt()) { if (user Phrase.charAt(i+1) >= 65 && uses Phrase.charAt(i+1)= 902 totalAsconym += user Phrase.charAt(i+1) return totalAcronym: public static void main( { Scanner scor = Scanner(myfile.txt); String inputPhrase: String usscasconym: inputPhrass = sur.nextInto; uses Assenym = create Acronym inputPhrase); System.println(user Asconym): There are at least 20 errors and imperfections in the code presentation above. List nine of them below. There are three bonus points if you can list twelve. If the error is on a specific line provide the line number.

Answer 1

The answer to this question is as follows:

The modified code is as follows:

import java.util.*;
public class MyClass {
public static void main(String args[]) {
Scanner sc=new Scanner(System.in);
String inputPhrase;
String userAcronym;
inputPhrase=sc.nextLine();
userAcronym=createAcronym(inputPhrase);
System.out.println(userAcronym);
}
public static String createAcronym(String userPhrase)
{
String totalAcronym;
int i;
totalAcronym="";
for(i=0;i<userPhrase.length();i++)
{
if(i!=userPhrase.length()-1)
{
  
if(i==0)
{

if(userPhrase.charAt(i)>=65 & userPhrase.charAt(i)<=90)
{
totalAcronym+=userPhrase.charAt(i);
}
}
else if(Character.isWhitespace(userPhrase.charAt(i)))
{
if(userPhrase.charAt(i+1)>=65 && userPhrase.charAt(i+1)<=90)
totalAcronym+=userPhrase.charAt(i+1);
  
}
}
}
return totalAcronym;
}
}

The list of errors is as follows:

1.Line 27: cannot convert the Int to String

2. Line 28 cannot find the variable userAcroynm

Line 8:

cannt find the variable named i

Line 9: The if condition is (i==0)

Line Declare the variable i instead of the j1 and replace in the for loop

Line 4: There is no type string in java in the string the s should be capital

Line 7: In for loop the valeu for the assignment should be = but not ==

Line 16: remove the value at the end of the if condition

Line 29: System.out.prinltn should be there instead of the system.print

Line 24: The scanner statement should be Scanner scnr=new Scanner(System.in);