Question

Only parts (e) and (f) is required

Thanks.

2. An 8 cylinder 5.6L (total displacement) 4-stroke diesel engine has a compression ratio of 19.3 and a cutoff ratio of 1.4. The temperature and pressure at the beginning of the compression stroke is 27°C and 100 kPa. The maximum pressure in the cycle is 7400 kPa. Assume variable properties (Table A-17). a. Draw the P-v diagram b. Determine the maximum temperature during the cycle c. Determine the amount of heat added during the cycle d. Determine the thermal efficiency of the cycle e. If the engine is operating at 2500 RPM, determine the net power output of the engine f. If the engine is operating at 2500 RPM and the diesel fuel has a heating value of 35.4 MJ/liter, determine the amount of fuel that is consumed during one hour of operation

Answer 1

Reference Book :

1.V.Ganesan "Internal Combustion Engine" 4th Edition.

AssUMPTION: By refering Most the book, I found that of Specific heat ratio , 8 = 1.4 8 Specific heat Capacity at const- pressure 7 cp = 10004 KJ keyak k сү 9 at const. Volume 00714 KJ ко-К R= Cpr Cy -284 KJ = 287 kJ /kg

e) Net power at N= 2500 rpm s' from My analyiss I found Ti = 300k T3 = 1372.37 k T4 = 480.5 K To=980.26 k Francisco Q = cp[T3-72) QR Сү [T4 - -T, 128.84 kJ lika - 393.68 kJ kg Work output Q QR 264.803, KJ KJ lkg Power output Work output x ma ma-mass flow rate of air ma P. Vi = Х ald RT 2

Swept volume , Vs 5.6L [Total displacement 3 = 0.0056 m V, - Swept volume + Clearrence Volume (Vc) P In the Question Clearence Volume is rust given. So, I assume Ve = 0 But for practical Case, Ve must be a positive value V=Vg 0.0056 3 100xo m 0.0056 х 2500 284 X 300 2 Ma = 8.13 kg ls for 8 cylinder for single cylinder Ma = 1.015 kg Is Power output = Hork output x ma = 264.803 x 8.13 Power olp = 2152.86 KW

f) N=2500 rpm Calorific Value , CoV = 3504 MJ Liter Total head added Qf CoV x Total displacement by fuel 35.4 MJ 5.6 liter - Liter Q1 = 198. 24 MJ Heat added added in Cp(T3 -T2) = mfx Of air ma MF Ma Cp (T3.-T2) Qf = 8,13 x 1004 ( 1372.37. 980.26) 6 1980 24 x m --3 16.14 X10 f kg lå amount of fuel consumed for the 16:14x60 x 3600 ther = 58.12 kg[For The