Question

A hydraulic lift uses a compressor to compress the hydraulic fluid with a moving piston (piston A) of radius RA = 4.75 cm. A second piston (piston B) of radius Rg = 18.52 cm is used at the lift to lift cars. What force must be applied by piston A to lift a 13,617N car with piston B?

Answer 1

Using Pascal's law, the pressure in both the pistons will be same. Let F1 force be applied at piston A and F2 force is received at piston B.

Force required at piston B = 13617N

Now, equating pressure in both the pistons

  $\frac{F_{1}}{\pi R_{A}^{2}}=\frac{F_{2}}{\pi R_{B}^{2}}$

  $\frac{F_{1}}{\pi (4.75)^{2}}=\frac{13617}{\pi (18.52)^{2}}$

$F_{1}=895.75N$

At piston A, 895.75N force must be applied to lift the car.