A hydraulic lift is designed to raise a 900 kg car. If one piston has a...

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Question

Answer 1

Answer #1

The weight of car = 900 kg * g = 900* 9.8 = 8820 N

To lift the car P1 = P2

area of piston 1 = pi*r1² = 3.14*0.35^{2 =} 0.38465 m²

area of piston 2 = pi*r2^{2 =} 3.14*0.02² = 0.001256 m²

force = preassure*area

which area has more we have to use that piston

i.e. 35 cm piston

Answer 2

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